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AHF    C    PROGRAM    SOLVING

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Iterative statement



Working with switch case



" ; " after loop



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Count positive, negative and zero untill (-1) is encountered




// AHF C PROGRAM SOLVING

//solving here ITERATIVES STATEMENTS type of programming problem

#include<stdio.h> #include<math.h> #define pf printf int main() { int number; int positive= 0,negative= 0,zero= 0,count=0; pf("\nEnter any number. Enter -1 to exit........\t: "); scanf("%d",&number); //this input will start the loop while(number!=-1) //ending condition of loop { if(number>0) positive++; else if(number&lg0) negative++; else zero++; count++; //counting for total given input pf("\nEnter any number. Enter -1 to exit........\t: "); scanf("%d",&number); //this input will stop the loop } //printing the required statement pf("\n\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\"); pf("\n\nCount of positive number= %d",positive); pf("\nCount of negative number= %d",negative); pf("\ncount of zero= %d",zero); pf("\nTotal given input= %d",count); return 0; }
OUTPUT:


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